Proof of |x| >= 0
Let \(x \in \mathbf{R}\), \(|x| \geq 0\).
For the absolute value function definition and other properties see here.
Proof:
By the definition of the absolute value function we have two cases:
- if \(x \geq 0\), then \(|x| = x\) and so \(|x| \geq 0\).
- if \(x < 0\), then \(|x| = -x\). Since \(x < 0\), then \(-x > 0\) so this means that \(|x| = -x > 0\). As required.
This second case definitely made me pause. By definition \(|x| = -x\). But \(x\) is negative. This means that \(-x\) is positive so \(|x|\) is positive!
\(\blacksquare\)
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