In an inner product space, the inner product determines the length of a vector. More generally, we can specify the length directly by defining a norm.

Definition (1.0) — Normed Space
Let \(V\) be a vector space over \(\mathbb{F}\), where \(\mathbb{F}=\mathbb{R}\) or \(\mathbb{F}=\mathbb{C}\). A norm on \(V\) is a function \(\|\cdot\|\colon V\to[0,\infty)\) satisfying the following properties for all \(\mathbf{u},\mathbf{v}\in V\) and \(\alpha\in\mathbb{F}\).
  1. Positive definiteness. \(\|\mathbf{v}\|\ge 0\), with equality if and only if \(\mathbf{v}=\mathbf{0}\).
  2. Absolute homogeneity. \(\|\alpha\mathbf{v}\|=|\alpha|\,\|\mathbf{v}\|\).
  3. Triangle inequality. \(\|\mathbf{u}+\mathbf{v}\|\le\|\mathbf{u}\|+\|\mathbf{v}\|\).
The pair \((V,\|\cdot\|)\) is called a normed space.

Every norm induces a metric on \(V\) given by

$$ d(\mathbf{u},\mathbf{v})=\|\mathbf{u}-\mathbf{v}\|. $$
Definition (1.1) — Banach Space
A Banach space is a normed space \((V,\|\cdot\|)\) in which every Cauchy sequence converges to a vector in \(V\). A sequence \((\mathbf{v}_n)\) is Cauchy if for every \(\epsilon>0\), there exists \(N\in\mathbb{N}\) such that \(\|\mathbf{v}_n-\mathbf{v}_m\|\lt\epsilon\) for all \(m,n\ge N\).

Example 1

Let \(C[a,b]\) be the space of continuous functions \(f\colon[a,b]\to\mathbb{F}\). Its supremum norm is

$$ \|f\|_\infty = \sup_{x\in[a,b]}|f(x)| = \max_{x\in[a,b]}|f(x)|. $$

Every Cauchy sequence in this norm converges uniformly to a function on \([a,b]\). The uniform limit of continuous functions is continuous, so the limit belongs to \(C[a,b]\). Thus \(C[a,b]\) is a Banach space.


Example 2

Let \((H,\langle\cdot,\cdot\rangle)\) be a Hilbert space. Its inner product induces the norm

$$ \|\mathbf{v}\|=\sqrt{\langle\mathbf{v},\mathbf{v}\rangle}. $$

A Hilbert space is complete in this norm by definition. Hence every Hilbert space is a Banach space.


Example 3

Let \(\mathbb{T}=\mathbb{R}/(2\pi\mathbb{Z})\) denote the circle. The space \(L^1(\mathbb{T})\) consists of equivalence classes of measurable functions \(f\colon\mathbb{T}\to\mathbb{C}\) satisfying

$$ \int_{-\pi}^{\pi}|f(x)|\,dx \lt \infty. $$

Two functions represent the same element if they agree almost everywhere. With the normalized norm

$$ \|f\|_{L^1} = \frac{1}{2\pi}\int_{-\pi}^{\pi}|f(x)|\,dx, $$

\(L^1(\mathbb{T})\) is a Banach space. Its norm fails the parallelogram identity, so no inner product induces this norm.


Example 4

The space \(\ell^1(\mathbb{N})\) consists of all absolutely summable sequences. It is given by

$$ \ell^1(\mathbb{N}) = \left\{ (c_n)_{n=1}^{\infty}\in\mathbb{F}^{\mathbb{N}} \,\middle|\, \sum_{n=1}^{\infty}|c_n| \lt \infty \right\}. $$

It is a Banach space with the norm

$$ \|(c_n)\|_1=\sum_{n=1}^{\infty}|c_n|. $$

Example 5

The space \(c_0\) consists of all sequences that converge to zero. It is given by

$$ c_0 = \left\{ (c_n)_{n=1}^{\infty}\in\mathbb{F}^{\mathbb{N}} \,\middle|\, \lim_{n\to\infty}c_n=0 \right\}. $$

Every sequence that converges to zero is bounded, so its supremum norm is finite. With the norm

$$ \|(c_n)\|_\infty=\sup_{n\in\mathbb{N}}|c_n|, $$

\(c_0\) is a Banach space. Indeed, \(c_0\) is a closed subspace of the Banach space of bounded sequences in the next example.


Example 6

The space of bounded sequences is

$$ \ell^\infty(\mathbb{N}) = \left\{ (c_n)_{n=1}^{\infty}\in\mathbb{F}^{\mathbb{N}} \,\middle|\, \sup_{n\in\mathbb{N}}|c_n| \lt \infty \right\}. $$

Its norm is

$$ \|(c_n)\|_\infty=\sup_{n\in\mathbb{N}}|c_n|. $$

To see why this space is complete, let \(x^{(k)}=(x_n^{(k)})_{n=1}^{\infty}\) be Cauchy in the supremum norm. For each fixed \(n\), the scalars \(x_n^{(k)}\) are Cauchy and have a limit \(x_n\). Given \(\epsilon>0\), choose \(K\) so that \(\|x^{(k)}-x^{(j)}\|_\infty \lt \epsilon/2\) for all \(k,j\ge K\). Letting \(j\to\infty\) in each coordinate gives

$$ |x_n^{(k)}-x_n|\le\epsilon/2 \qquad \text{for every } n\in\mathbb{N} \text{ and } k\ge K. $$

Taking \(k=K\) shows that \(x=(x_n)\) is bounded, since \(x^{(K)}\) is bounded. Taking the supremum over \(n\) shows that \(\|x^{(k)}-x\|_\infty\to 0\). Thus \(\ell^\infty(\mathbb{N})\) is a Banach space.


References

  • SFSU Fourier Analysis by Professor Chun-Kit Lai
  • Fourier Analysis: An Introduction by Elias M.Stein and Rami Shakarchi